messages.AcceptUrlAuth

class pyrogram.raw.functions.messages.AcceptUrlAuth

Use this to accept a Seamless Telegram Login authorization request, for more info click here »

Details:

• Layer: 223

• ID: 67A3F0DE

Parameters:

• write_allowed (bool, optional) – Set this flag to allow the bot to send messages to you (if requested)

• share_phone_number (bool, optional)

• peer (InputPeer, optional) – The location of the message

• msg_id (int 32-bit, optional) – Message ID of the message with the login button

• button_id (int 32-bit, optional) – ID of the login button

• url (str, optional) – URL used for link URL authorization, click here for more info »

• match_code (str, optional) – N/A

Returns:

UrlAuthResult

TL Schema

messages.acceptUrlAuth#67a3f0de
flags:#
write_allowed:flags.0?true
share_phone_number:flags.3?true
peer:flags.1?InputPeer
msg_id:flags.1?int
button_id:flags.1?int
url:flags.2?string
match_code:flags.4?string

= UrlAuthResult

Parameter Tree

Example

await app.invoke(
    AcceptUrlAuth(
        write_allowed=None,
        share_phone_number=None,
        peer=await app.resolve_peer(chat_id),
        msg_id=0,
        button_id=0,
        url="https://google.com",
        match_code="text",
    )
)